PSLE Math 2023 Paper 2 Question 10
(Average of Three Boxes Question)
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PSLE Math 2023 Paper 2 Question 10
Total mass of A, B and C = 240g x 3
Based on the diagram, A + B = C
A + B → 720g ÷ 2 = 360g
To get smallest possible difference between A and B → B has to be as large as possible while A has to be as small as possible.
Largest possible value of B = 99g (2 digit number)
Total of A and C = 360g - 99g = 261g
Smallest possible difference between A and B = 261g - 99g
= 162g